-5x(x+4)=20x^2+4

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Solution for -5x(x+4)=20x^2+4 equation: 



-5x(x+4)=20x^2+4

We move all terms to the left:

-5x(x+4)-(20x^2+4)=0

We multiply parentheses

-5x^2-20x-(20x^2+4)=0

We get rid of parentheses

-5x^2-20x^2-20x-4=0

We add all the numbers together, and all the variables

-25x^2-20x-4=0

a = -25; b = -20; c = -4;
Δ = b2-4ac
Δ = -202-4·(-25)·(-4)
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{20}{-50}=-2/5$

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